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Proof step 6 from proof crash-neutral-unmap (previous step)

m < # avols[v], ebm-cons(avols), ebm-cons(avols0), v ∈ avols, avols ⊆ avols0 ⊦ avols[v, avols[v][m, unmapped]] ⊆ avols0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information