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Proof step 16 from proof inv-read (previous step)

m2 < # avols[v], ebm-cons(avols), v ∈ avols, m1 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪choose buf1 with # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n) in buf := buf1⟫ true, err0 = ESUCCESS

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Proof step 17:
# buf1 = # buf, m2 < # avols[v], ebm-cons(avols), range=(buf1, 0, buf, 0, n0), range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪buf := buf1⟫ true, err0 = ESUCCESS
Proof step 18:
m2 < # avols[v], ebm-cons(avols), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err0 = ESUCCESS, ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n)
Proof step 21:
m2 < # avols[v], ebm-cons(avols), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ err0 = ESUCCESS, ∀ buf1. # buf1 = # buf → range=(buf1, 0, buf, 0, n0) → # buf ≥ n0 + n

Proof step 16 from proof inv-read (previous step)

Heuristic symbolic execution applied rule choose right

And obtained the following new goals

Rule argument

Additional information