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Proof step 9 from proof inv-read (previous step)

m2 < # avols[v], ebm-cons(avols), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err0 = ESUCCESS then if ¬ avols[v][m2].mapped? then buf := fill(buf, empty, n0, n) else buf := copy(avols[v][m2].data, m1, buf, n0, n) else choose buf1 with # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n) in buf := buf1⟫ true

Heuristic conditional right split applied rule if right

And obtained the following new goals

Proof step 10:
err0 = ESUCCESS, m2 < # avols[v], ebm-cons(avols), v ∈ avols, m1 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if ¬ avols[v][m2].mapped? then buf := fill(buf, empty, n0, n) else buf := copy(avols[v][m2].data, m1, buf, n0, n)⟫ true
Proof step 16:
m2 < # avols[v], ebm-cons(avols), v ∈ avols, m1 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪choose buf1 with # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n) in buf := buf1⟫ true, err0 = ESUCCESS

Rule argument

pos: right 1

Proof step 9 from proof inv-read (previous step)

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

Additional information