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Proof step 19 from proof inv-read (previous step)

m2 < # avols[v], ebm-cons(avols), v ∈ avols, m1 + n ≤ LEB_SIZE, n0 + n ≤ # buf, ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, # buf - n0 + n)

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 20:
# buf = n1 + n0 + n, m2 < # avols[v], ebm-cons(avols), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, n1)

Rule argument

spec: nat name: elim-sub seq: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n subst: [m, n, n0] → [# buf, n0 + n, n1]

Additional information

Used simplifier rules: n ≤ m ⊦ n0 = m - n ↔ m = n0 + n; (elim) Used terms: # buf, n0 + n, n1