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Proof step 20 from proof inv-read (previous step)

# buf = n1 + n0 + n, m2 < # avols[v], ebm-cons(avols), v ∈ avols, n0 + n ≤ # buf, m1 + n ≤ LEB_SIZE, ⌊err0⌋ ⊦ ∃ buf1. # buf1 = # buf ∧ range=(buf1, 0, buf, 0, n0) ∧ range=(buf1, n0 + n, buf, n0 + n, n1)

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: buf

Additional information

Used simplifier rules: ⊦ range=(buf, n, buf, n, m) ↔ n + m ≤ # buf; (s)% ⊦ n + 0 = n; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic% ⊦ m ≤ m; (s)% ⊦ m ≤ n ↔ ¬ n < m; (ss)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ m < n → n ≠ 0; (s)% ⊦ m + m0 < n → ¬ n + n0 < m; (s) Used terms: buf