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Proof step 2 from proof inv-recover (previous step)

ebm-cons(avols), avols ⊆ avols0, ebm-cons(avols) → ebm-cons(avols0) ⊦ ⟪ebm_recover#(; avols0; err)⟫ (err = ESUCCESS → ebm-cons(avols0))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information