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Proof step 3 from proof inv-recover (previous step)

ebm-cons(avols), ebm-cons(avols0), avols ⊆ avols0 ⊦ ⟪ebm_recover#(; avols0; err)⟫ (err = ESUCCESS → ebm-cons(avols0))

Heuristic nonrecursive calls applied rule call right

And obtained the following new goals

Proof step 4:
avols = avols0, ebm-cons(avols0), ebm-cons(avols1), avols1 ⊆ avols0 ⊦ ⟪fail_or_success#(; ; err); if err ≠ ESUCCESS then avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Rule argument

pos: right 1

Additional information

Used simplifier rules: recover: ⊦ ;