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Proof step 7 from proof inv-recover (previous step)

avols = avols0, err = err0, ebm-cons(avols1), ebm-cons(avols0), avols1 ⊆ avols0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪if err ≠ ESUCCESS then avols := ?⟫ (err = ESUCCESS → ebm-cons(avols))

Heuristic conditional right split applied rule if right

And obtained the following new goals

Rule argument

pos: right 1

Additional information