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Proof step 9 from proof inv-recover (
previous step
)
avols = avols0, err = ESUCCESS, err = err0, ebm-cons(avols0), ebm-cons(avols1), avols1 ⊆ avols0, ⌊err0⌋ ∨ err0 = ESUCCESS ⊦ ⟪skip⟫ (err = ESUCCESS → ebm-cons(avols))
Heuristic symbolic execution applied rule skip right
And closed the goal!
Rule argument
Additional information
Used simplifier rules: ⊦ ¬ ⌊ESUCCESS⌋ ; (s)