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Proof step 4 from proof in-rm-v-in (previous step)

eq-entry(n, lref) ∈ eqent + q0 - v, ∀ n, lref, v. eq-entry(n, lref) ∈ q0 - v → (∃ n. eq-entry(n, lref) ∈ q0) ⊦ ∃ n. eq-entry(n, lref) ∈ eqent + q0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
eq-entry(n, lref) ∈ (eqent.lebref ≠ none ∧ eqent.lebref.vol = v ⊃ q0 - eqent.lebref.vol;eqent ' + (q0 - v)), ∀ n, lref, v. eq-entry(n, lref) ∈ q0 - v → (∃ n. eq-entry(n, lref) ∈ q0) ⊦ ∃ n0. eq-entry(n0, lref) = eqent ∨ eq-entry(n0, lref) ∈ q0

Rule argument

Additional information

Used simplifier rules: queue-rm-v-rec: ⊦ eqent ' + q - v = (eqent.lebref ≠ none ∧ eqent.lebref.vol = v ⊃ q - v ;eqent ' + (q - v) );% ⊦ eqent ∈ eqent0 ' + q ↔ eqent = eqent0 ∨ eqent ∈ q; (s)%a: ⊦ (q + q0) + q1 = q + q0 + q1; from specification list[erasequeue-base]% ⊦ eqent + q = eqent ' + q; (s)