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Proof step 5 from proof in-rm-v-in (previous step)

eq-entry(n, lref) ∈ (eqent.lebref ≠ none ∧ eqent.lebref.vol = v ⊃ q0 - eqent.lebref.vol;eqent ' + (q0 - v)), ∀ n, lref, v. eq-entry(n, lref) ∈ q0 - v → (∃ n. eq-entry(n, lref) ∈ q0) ⊦ ∃ n0. eq-entry(n0, lref) = eqent ∨ eq-entry(n0, lref) ∈ q0

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: erasequeueentry name: elim seq: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref) subst: [eqent, m, lref] → [eqent, m, lref1]

Additional information

Used simplifier rules: ⊦ m = eqent.pnum ∧ lref = eqent.lebref ↔ eqent = eq-entry(m, lref); (elim) Used terms: eqent, m, lref1