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Proof step 13 from proof in-rm-v-same (previous step)

eq-entry(n, v × m) ∈ (v0 = v ⊃ q0 - v;eq-entry(m0, v0 × m1) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 14:
v0 = v, eq-entry(n, v × m) ∈ (v0 = v ⊃ q0 - v;eq-entry(m0, v0 × m1) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦
Proof step 16:
eq-entry(n, v × m) ∈ (v0 = v ⊃ q0 - v;eq-entry(m0, v0 × m1) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦ v0 = v

Rule argument

fma: v0 = v

Additional information

Used formulas: v0 = v