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Proof step 14 from proof in-rm-v-same (
previous step
)
v0 = v, eq-entry(n, v × m) ∈ (v0 = v ⊃ q0 - v;eq-entry(m0, v0 × m1) ' + (q0 - v)), ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 15
:
eq-entry(n, v × m) ∈ q0 - v, ∀ n, v, m. ¬ eq-entry(n, v × m) ∈ q0 - v ⊦
Rule argument
Additional information