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Proof step 23 from proof valid-sqns-extract2-sqn-h (previous step)

apebs[n1] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), apebs[m1] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n1 + 1 < # apebs, m1 < # apebs, n1 < # apebs, n1 < m1, valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)), n1 < m1 ∧ m1 ≤ # apebs ∧ valid-peb(v, m, apebs[n1]) → (∃ bag. valid-sqns(v, m, apebs, m1) = bag ++ apebs[n1].vidhdr.sqn) ⊦ m1 = n1, ∃ bag. valid-sqns(v, m, apebs, m1) ++ avhdr.sqn = bag ++ avhdr.sqn ++ avhdr0.sqn

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 24:
apebs[n1] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), apebs[m1] = mkpeb(aehdr, avhdr, buf, m0, boolvar), valid-sqns(v, m, apebs, m1) = bag ++ avhdr0.sqn, n1 + 1 < # apebs, m1 < # apebs, n1 < # apebs, n1 < m1, valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ m1 = n1, ∃ bag. valid-sqns(v, m, apebs, m1) ++ avhdr.sqn = bag ++ avhdr.sqn ++ avhdr0.sqn

Rule argument

Additional information

Used simplifier rules: ⊦ mkpeb(aehdr, avhdr, buf, m, boolvar).vidhdr = avhdr; (s)%⊦ valid-peb(v0, m0, apeb) → (valid-peb(v1, m1, apeb) ↔ v0 = v1 ∧ m0 = m1); (s)% ⊦ m < n → m ≤ n; (s)