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Proof step 24 from proof valid-sqns-extract2-sqn-h (previous step)

apebs[n1] = mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0), apebs[m1] = mkpeb(aehdr, avhdr, buf, m0, boolvar), valid-sqns(v, m, apebs, m1) = bag ++ avhdr0.sqn, n1 + 1 < # apebs, m1 < # apebs, n1 < # apebs, n1 < m1, valid-peb(v, m, mkpeb(aehdr0, avhdr0, buf0, m2, boolvar0)), valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ m1 = n1, ∃ bag. valid-sqns(v, m, apebs, m1) ++ avhdr.sqn = bag ++ avhdr.sqn ++ avhdr0.sqn

User applied rule exists right

And closed the goal!

Rule argument

pos: right 2 terms: bag abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ bag ++ n ++ n0 = bag2 ++ n ↔ bag ++ n0 = bag2; (ss) Used terms: bag