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Proof step 12 from proof valid-sqns-subseteq-h (previous step)

apebs[n] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n0 + 1 < # apebs, n0 < n, n < # apebs, n0 < # apebs, valid-peb(v, m, apebs[n]), n0 ≤ n + 1, valid-sqns(v, m, apebs, n0) ⊆ valid-sqns(v, m, apebs, n) ⊦ valid-sqns(v, m, apebs, n0) ⊆ valid-sqns(v, m, apebs, n) ++ avhdr.sqn

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
apebs[n] = mkpeb(aehdr, avhdr, buf, m0, boolvar), n0 < # apebs, n < # apebs, n0 < n, n0 + 1 < # apebs, valid-peb(v, m, mkpeb(aehdr, avhdr, buf, m0, boolvar)), n0 ≤ n + 1, valid-sqns(v, m, apebs, n0) ⊆ valid-sqns(v, m, apebs, n) ⊦ valid-sqns(v, m, apebs, n0) ⊆ valid-sqns(v, m, apebs, n) ++ avhdr.sqn

Proof step 12 from proof valid-sqns-subseteq-h (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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