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Theorem valid-sqns-subseteq-h
⊦ n0 ≤ n1 ∧ n1 ≤ # apebs → valid-sqns(v, m, apebs, n0) ⊆ valid-sqns(v, m, apebs, n1)
Type: A user defined theorem
Validity: The proof is valid.
Features: ss, lss,
Comment:
Used by:
valid-sqns-subseteq
,
Used by units in proved state:
Proof exists?: Yes
View
the proof
Infos about the proof
Proved?: Yes
Interactions: 9
Proof steps: 20
Used lemmas:
valid-sqns-rec
,
valid-sqns-base
,
Used spec theorems:
bag-union
/nat-bag/
count-subset
bag-basic
/nat-bag/
count-insert
nat
/
anti
Used simplifier rules:
nat
/
lez
nat
/
lez-01
bag-union
/nat-bag/
subset-emp
nat-basic
/
succ
nat-basic
/
trans
nat-basic
/
lf
bag-union
/nat-bag/
union-empty
bag-max
/
bag-union-one
apeb
/
elim
nat
/
le-def
nat-basic
/
l-02
nat
/
let
nat
/
lels
nat
/
ler
nat
/
lels-03
nat
/
lep
nat-basic
/
a
nat-basic
/
c
bag-union
/nat-bag/
union-subset
bag-union
/nat-bag/
union-ass
bag-union
/nat-bag/
union-com
nat
/
anti
nat
/
lels-02
nat
/
les
nat
/
eqle-one
nat-basic
/
f
nat-basic
/
lf-01
nat
/
fle
nat-basic
/
oz
nat-basic
/
eq-02
nat
/
lep-02
nat-basic
/
s-04
nat-basic
/
ref
nat
/
succ-01
bag-union
/nat-bag/
union-subset-inj
bag-union
/nat-bag/
subset-refl