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Theorem disjoint
⊦ st0 ⊥ st1 ↔ (∀ a. ¬ a ∈ st0 ∨ ¬ a ∈ st1)
Type: An axiom
Validity: The proof is valid.
Features:
Comment:
Used by:
disjoint-in-left
,
disjoint-in-right
,
disjoint-left-empty
,
disjoint-move-left
,
disjoint-right-empty
,
Used by units in proved state:
encoding-vtbl
,
Proof exists?: No