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Proof step 3 from proof lf-cmp-peb (previous step)

n0 < n + m, cmp(apebs, apeb, n, m), n ≤ n0 ⊦ apebs[n0] = apeb, m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ cmp(apebs, apeb, m, n) ↔ (∀ n0. n0 < n → apebs[m + n0] = apeb)
Proof step 5:
n0 < n + m, n ≤ n0, ∀ n0. n0 < m → apebs[n + n0] = apeb ⊦ apebs[n0] = apeb, m = 0

Rule argument

spec: array-copy, inst: apebs name: Cmp-elem seq: ⊦ cmp(apebs, apeb, m, n) ↔ (∀ n0. n0 < n → apebs[m + n0] = apeb) subst: [n, m, apeb, apebs] → [m, n, apeb, apebs] flags: <all paths>

Additional information

Used terms: m, n, apeb, apebs