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Proof step 5 from proof lf-cmp-peb (previous step)

n0 < n + m, n ≤ n0, ∀ n0. n0 < m → apebs[n + n0] = apeb ⊦ apebs[n0] = apeb, m = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ m ≤ n ↔ (∃ n0. m + n0 = n)
Proof step 7:
n0 < n + m, ∀ n0. n0 < m → apebs[n + n0] = apeb, ∃ n1. n + n1 = n0 ⊦ apebs[n0] = apeb, m = 0

Rule argument

spec: nat name: le-addex seq: ⊦ m ≤ n ↔ (∃ n0. m + n0 = n) subst: [n, m] → [n0, n] flags: <all paths>

Additional information

Used terms: n0, n