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Proof step 3 from proof ls-valid-global-sqn-vtbl (previous step)

valid-global-sqn(apebs, sqnum), valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), sqnum ≤ valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs).max ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ valid-global-sqn(apebs, n) ↔ (∀ v, m. valid-sqns(v, m, apebs) ≠ ∅ → n > valid-sqns(v, m, apebs).max)
Proof step 5:
valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), sqnum ≤ valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs).max, ∀ v, m. valid-sqns(v, m, apebs) ≠ ∅ → sqnum > valid-sqns(v, m, apebs).max ⊦

Rule argument

spec: ubi-base name: valid-global-sqn seq: ⊦ valid-global-sqn(apebs, n) ↔ (∀ v, m. valid-sqns(v, m, apebs) ≠ ∅ → n > valid-sqns(v, m, apebs).max) subst: [n, apebs] → [sqnum, apebs] flags: <all paths>

Additional information

Used terms: sqnum, apebs