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Proof step 5 from proof ls-valid-global-sqn-vtbl (previous step)

valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), sqnum ≤ valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs).max, ∀ v, m. valid-sqns(v, m, apebs) ≠ ∅ → sqnum > valid-sqns(v, m, apebs).max ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
valid-vtbl(apebs, vols, wlar, vtblpnum), valid-wl(apebs, wlar), sqnum ≤ valid-sqns(VTBL_VOLID, VTBL_LNUM, apebs).max, ∀ v, m. valid-sqns(v, m, apebs) ≠ ∅ → valid-sqns(v, m, apebs).max < sqnum ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m > n ↔ n < m; (s)