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Proof step 6 from proof valid-eraseqd-nodups1 (previous step)

eqent = eq-entry(m1, lref), valid-eraseq(q + q1), m ∈ eqent ' + q, m ∈ q1, ∀ q0, m0. ¬ valid-eraseq(q + q0) ∨ ¬ m0 ∈ q0 ∨ ¬ m0 ∈ q ⊦ m1 ∈ q1, m1 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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