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Proof step 7 from proof valid-eraseqd-nodups1 (previous step)

valid-eraseq(q + q1), m ∈ q1, m ∈ eq-entry(m1, lref) ' + q, ∀ q0, m0. ¬ valid-eraseq(q + q0) ∨ ¬ m0 ∈ q0 ∨ ¬ m0 ∈ q ⊦ m1 ∈ q, m1 ∈ q1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 8:
⊦ n ∈ q0 + q1 ↔ n ∈ q0 ∨ n ∈ q1
Proof step 9:
valid-eraseq(q + q1), m ∈ q1, ∀ q0, m0. ¬ valid-eraseq(q + q0) ∨ ¬ m0 ∈ q0 ∨ ¬ m0 ∈ q, m ∈ eq-entry(m1, lref) ' ∨ m ∈ q ⊦ m1 ∈ q1, m1 ∈ q

Rule argument

spec: erasequeue name: in-concat seq: ⊦ n ∈ q0 + q1 ↔ n ∈ q0 ∨ n ∈ q1 subst: [q1, q0, n] → [q, eq-entry(m1, lref) ', m] flags: <all paths>

Additional information

Used terms: q, eq-entry(m1, lref) ', m