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Proof step 9 from proof valid-eraseqd-nodups1 (previous step)

valid-eraseq(q + q1), m ∈ q1, ∀ q0, m0. ¬ valid-eraseq(q + q0) ∨ ¬ m0 ∈ q0 ∨ ¬ m0 ∈ q, m ∈ eq-entry(m1, lref) ' ∨ m ∈ q ⊦ m1 ∈ q1, m1 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 10:
valid-eraseq(q + q1), m ∈ q1, m ∈ q, ∀ q0, m0. ¬ valid-eraseq(q + q0) ∨ ¬ m0 ∈ q0 ∨ ¬ m0 ∈ q ⊦ m1 ∈ q, m1 ∈ q1

Rule argument

Additional information

Used simplifier rules: ⊦ n ∈ eq-entry(m, lref) ' ↔ n = m; (s)