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Proof step 8 from proof valid-eraseqw-free (previous step)

wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0), ∀ n. n ∈ q0 + eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q1, m ∈ q0

User applied rule all left

And obtained the following new goals

Proof step 9:
n ∈ q0 + eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ wlar[n].status = erasing, wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0) ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q0, m ∈ q1

Rule argument

pos: left 2 terms: n abort: F discard: T computed: T

Additional information

Used terms: n