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Proof step 9 from proof valid-eraseqw-free (previous step)

n ∈ q0 + eq-entry(m, lref) ' + q1 ↔ n < # wlar ∧ wlar[n].status = erasing, wlar[m, wl-entry(m0, stat)][n] = wl-entry(m1, stat0) ⊦ n ∈ q0 + q1 ↔ n < # wlar ∧ stat0 = erasing, stat = erasing, m ∈ q0, m ∈ q1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Rule argument

spec: wlentry name: elim-02 seq: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat) subst: [wle, m, stat] → [wlar[n], m2, stat1]

Additional information

Used simplifier rules: ⊦ m = wle.ec ∧ stat = wle.status ↔ wle = wl-entry(m, stat); (elim) Used terms: wlar[n], m2, stat1