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Proof step 17 from proof valid-eraseqw-subarray-shift (previous step)

n ∈ q ↔ n < n ∧ wlar[n].status = erasing, wlar[n0] = wl-entry(m0, erasing), n0 + 1 < # wlar, n < # wlar, n0 < n, n0 < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing, n0 ∈ q

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
wlar[n0] = wl-entry(m0, erasing), n0 < # wlar, n0 < n, n < # wlar, n0 + 1 < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing, n0 ∈ q, n ∈ q

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ n < n; (s)