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Proof step 18 from proof valid-eraseqw-subarray-shift (previous step)

wlar[n0] = wl-entry(m0, erasing), n0 < # wlar, n0 < n, n < # wlar, n0 + 1 < # wlar, ∀ n0. n0 ∈ q ↔ n0 < n ∧ wlar[n0].status = erasing ⊦ n0 = n, stat = erasing, n0 ∈ q, n ∈ q

Heuristic quantifier applied rule all left

And closed the goal!

Rule argument

pos: left 6 terms: n0

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).status = stat; (s) Used terms: n0