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Proof step 11 from proof valid-eraseqw-use (previous step)

wlar[n] = wl-entry(m0, stat), wlar[n, wl-entry(m1, used)][n0] = wl-entry(m, stat0), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n0 ∈ q ↔ n0 < # wlar ∧ stat0 = erasing, stat = erasing

Heuristic weak cut applied rule cut formula

And obtained the following new goals

Proof step 12:
wlar[n, wl-entry(m1, used)][n0] = wl-entry(m, stat0), wlar[n] = wl-entry(m0, stat), n0 = n, ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n0 ∈ q ↔ n0 < # wlar ∧ stat0 = erasing, stat = erasing
Proof step 18:
wlar[n, wl-entry(m1, used)][n0] = wl-entry(m, stat0), wlar[n] = wl-entry(m0, stat), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n0 ∈ q ↔ n0 < # wlar ∧ stat0 = erasing, n0 = n, stat = erasing

Rule argument

fma: n0 = n

Additional information

Used formulas: n0 = n