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Proof step 18 from proof valid-eraseqw-use (previous step)

wlar[n, wl-entry(m1, used)][n0] = wl-entry(m, stat0), wlar[n] = wl-entry(m0, stat), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n0 ∈ q ↔ n0 < # wlar ∧ stat0 = erasing, n0 = n, stat = erasing

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 19:
wlar[n] = wl-entry(m0, stat), wlar[n0] = wl-entry(m, stat0), ∀ n. n ∈ q ↔ n < # wlar ∧ wlar[n].status = erasing ⊦ n0 ∈ q ↔ n0 < # wlar ∧ stat0 = erasing, n0 = n, stat = erasing

Rule argument

Additional information

Used simplifier rules: ⊦ m ≠ n → wlar[n, wle][m] = wlar[m]; (s)