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Proof step 2 from proof indices-erasing-eraseq (previous step)

indices-erasing(wlar0, nx), valid-eraseq(wlar0, q0), valid-eraseq(wlar1, q1), q0 ⊆ q1 ⊦ indices-erasing(wlar1, nx)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information