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Proof step 3 from proof indices-erasing-eraseq (previous step)

indices-erasing(wlar0, nx), valid-eraseq(wlar1, q1), valid-eraseq(wlar0, q0), q0 ⊆ q1 ⊦ indices-erasing(wlar1, nx)

User applied rule structural induction

And obtained the following new goals

Proof step 4:
indices-erasing(wlar0, m + nx0), valid-eraseq(wlar0, q0), valid-eraseq(wlar1, q1), q0 ⊆ q1, ∀ wlar0, wlar1, q1, q0. indices-erasing(wlar0, nx0) ∧ valid-eraseq(wlar1, q1) ∧ valid-eraseq(wlar0, q0) ∧ q0 ⊆ q1 → indices-erasing(wlar1, nx0) ⊦ indices-erasing(wlar1, m + nx0)

Rule argument

indvar: nx

Additional information

Used simplifier rules: indices-erasing-base: ⊦ indices-erasing(wlar, []);%nat-list freely generated by [], +;;