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Proof step 26 from proof valid-eraseq-stronger-one (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf, m0, boolvar), m < # apebs, valid-peb(v, m1, mkpeb(aehdr, avhdr, buf, m0, boolvar)), lref ≠ none → valid-peb(lref.vol, lref.leb, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ∧ avhdr.sqn ≠ valid-sqns(lref.vol, lref.leb, apebs).max, lref = none → ¬ valid-peb(mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ lref = v × m1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 27:
apebs[m] = mkpeb(aehdr, avhdr, buf, m0, boolvar), m < # apebs, valid-peb(lref.vol, lref.leb, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ avhdr.sqn = valid-sqns(lref.vol, lref.leb, apebs).max, lref = none, lref = lref.vol × lref.leb

Rule argument

Additional information

Used simplifier rules: ⊦ valid-peb(v0, m0, apeb) → (valid-peb(v1, m1, apeb) ↔ v0 = v1 ∧ m0 = m1); (s)% ⊦ valid-peb(v, m, apeb) → valid-peb(apeb); (ss)