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Proof step 27 from proof valid-eraseq-stronger-one (previous step)

apebs[m] = mkpeb(aehdr, avhdr, buf, m0, boolvar), m < # apebs, valid-peb(lref.vol, lref.leb, mkpeb(aehdr, avhdr, buf, m0, boolvar)) ⊦ avhdr.sqn = valid-sqns(lref.vol, lref.leb, apebs).max, lref = none, lref = lref.vol × lref.leb

Heuristic elimination applied rule insert elim lemma

And closed the goal!

Rule argument

spec: lebref name: elim seq: ⊦ lref ≠ none → (v = lref.vol ∧ m = lref.leb ↔ lref = v × m) subst: [lref, v, m] → [lref, v, m1]

Additional information

Used simplifier rules: ⊦ lref ≠ none → (v = lref.vol ∧ m = lref.leb ↔ lref = v × m); (elim) Used terms: lref, v, m1