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Proof step 19 from proof in-ecs-n (previous step)

wlar[n] = wl-entry(m1, stat0), wlar[n0] = wl-entry(m0, stat), n0 < # wlar, n < # wlar, n ≤ n0, n0 ≤ # wlar → (m1 ∈ ecs(wlar, n0) ↔ (∃ n1. n1 < n0 ∧ wlar[n1].ec = m1)) ⊦ m1 = m0, m1 ∈ ecs(wlar, n0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
wlar[n0] = wl-entry(m0, stat), wlar[n] = wl-entry(m1, stat0), n < # wlar, n0 < # wlar, n ≤ n0 ⊦ m1 = m0, m1 ∈ ecs(wlar, n0), ∃ n1. n1 < n0 ∧ wlar[n1].ec = m1

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → m ≤ n; (s)