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Proof step 20 from proof in-ecs-n (previous step)

wlar[n0] = wl-entry(m0, stat), wlar[n] = wl-entry(m1, stat0), n < # wlar, n0 < # wlar, n ≤ n0 ⊦ m1 = m0, m1 ∈ ecs(wlar, n0), ∃ n1. n1 < n0 ∧ wlar[n1].ec = m1

User applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: n abort: F discard: T computed: F

Additional information

Used simplifier rules: ⊦ wl-entry(m, stat).ec = m; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m ≤ n → (n ≤ m ↔ m = n); (s)%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic% ⊦ m ≤ m; (s)% ⊦ wl-entry(m, stat) = wl-entry(m0, stat0) ↔ m = m0 ∧ stat = stat0; (ws) Used terms: n