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Proof step 6 from proof valid-peb0-imp-valid-peb (previous step)

m = m0, v = v0, aehdr.valid?, m2 ≠ 0 → m2 ≤ datasize(buf) ∧ m3 = checksum(buf, m2) ⊦ ∃ m4, m5, m6. avidhdr(v0, m0, m1, m2, m3) = avidhdr(v, m, m4, m5, m6) ∧ (m5 ≠ 0 → m5 ≤ datasize(buf) ∧ m6 = checksum(buf, m5))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 7:
aehdr.valid?, m2 ≠ 0 → m2 ≤ datasize(buf) ∧ m3 = checksum(buf, m2) ⊦ ∃ m4, m5, m6. avidhdr(v0, m0, m1, m2, m3) = avidhdr(v0, m0, m4, m5, m6) ∧ (m5 ≠ 0 → m5 ≤ datasize(buf) ∧ m6 = checksum(buf, m5))

Proof step 6 from proof valid-peb0-imp-valid-peb (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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