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Proof step 7 from proof valid-peb0-imp-valid-peb (previous step)

aehdr.valid?, m2 ≠ 0 → m2 ≤ datasize(buf) ∧ m3 = checksum(buf, m2) ⊦ ∃ m4, m5, m6. avidhdr(v0, m0, m1, m2, m3) = avidhdr(v0, m0, m4, m5, m6) ∧ (m5 ≠ 0 → m5 ≤ datasize(buf) ∧ m6 = checksum(buf, m5))

Heuristic quantifier applied rule exists right

And closed the goal!

Rule argument

pos: right 1 terms: m1, m2, m3

Additional information

Used terms: m1, m2, m3