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Proof step 7 from proof min-0 (previous step)

(n0 < min(n1, n2) ⊃ n0;min(n1, n2)) = 0 ⊦ n0 = 0, n1 = 0, n2 = 0

Heuristic nonsplitting cut applied rule cut formula

And obtained the following new goals

Proof step 8:
(n0 < min(n1, n2) ⊃ n0;min(n1, n2)) = 0 ⊦ n0 = 0, n1 = 0, n2 = 0, n0 < min(n1, n2)

Rule argument

fma: n0 < min(n1, n2)

Additional information

Used formulas: n0 < min(n1, n2)