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Proof step 8 from proof min-0 (previous step)

(n0 < min(n1, n2) ⊃ n0;min(n1, n2)) = 0 ⊦ n0 = 0, n1 = 0, n2 = 0, n0 < min(n1, n2)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
min(n1, n2) = 0 ⊦ n0 = 0, n1 = 0, n2 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ 0 ≤ m; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)