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Proof step 22 from proof align-down-app-same (previous step)

# buf0 = m0 * EB_PAGE_SIZE + n0, # buf0 + # buf1 = m1 * EB_PAGE_SIZE + n1, n0 < EB_PAGE_SIZE, n1 < EB_PAGE_SIZE, n0 + # buf1 < EB_PAGE_SIZE, n < m1 * EB_PAGE_SIZE, m0 * EB_PAGE_SIZE < m1 * EB_PAGE_SIZE, (n0 = 0 ⊃ # buf0;m0 * EB_PAGE_SIZE) ≤ n ⊦ m1 = 0, n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 23:
# buf0 = m0 * EB_PAGE_SIZE + n0, # buf0 + # buf1 = m1 * EB_PAGE_SIZE + n1, m0 < m1, n0 < EB_PAGE_SIZE, n1 < EB_PAGE_SIZE, n0 + # buf1 < EB_PAGE_SIZE, n < m1 * EB_PAGE_SIZE, m0 * EB_PAGE_SIZE ≤ n ⊦ n0 = 0

Rule argument

Additional information

Used simplifier rules: fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ EB_PAGE_SIZE ≠ 0; (s)% ⊦ m0 * m < m0 * n ↔ m0 ≠ 0 ∧ m < n; (ws)