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Proof step 23 from proof align-down-app-same (previous step)

# buf0 = m0 * EB_PAGE_SIZE + n0, # buf0 + # buf1 = m1 * EB_PAGE_SIZE + n1, m0 < m1, n0 < EB_PAGE_SIZE, n1 < EB_PAGE_SIZE, n0 + # buf1 < EB_PAGE_SIZE, n < m1 * EB_PAGE_SIZE, m0 * EB_PAGE_SIZE ≤ n ⊦ n0 = 0

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: ⊦ n0 < n ∧ n1 < n → (m * n + n0 = m0 * n + n1 ↔ m = m0 ∧ n0 = n1); (ws)%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%mult-c: ⊦ m * n = n * m; from specification nat-mult%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%lf-02: ⊦ m < n ∧ m = n0 → n0 < n; (forward) from specification nat-basic%lf-01: ⊦ m < n ∧ n = n0 → m < n0; (forward) from specification nat-basic% ⊦ m < n → ¬ n < m; (s)