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Proof step 12 from proof subarray-longer-eq-eq (previous step)

n0 < n, ∀ n1. n1 < n + m → copy(ar0, 0, mkarray(n + m), 0, n + m)[n1] = copy(ar1, 0, mkarray(n + m), 0, n + m)[n1] ⊦ ar0[n0] = ar1[n0]

User applied rule all left

And obtained the following new goals

Proof step 13:
n0 < n, n0 < n + m → copy(ar0, 0, mkarray(n + m), 0, n + m)[n0] = copy(ar1, 0, mkarray(n + m), 0, n + m)[n0] ⊦ ar0[n0] = ar1[n0]

Rule argument

pos: left 2 terms: n0 abort: F discard: T computed: F

Additional information

Used terms: n0