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Proof step 13 from proof subarray-longer-eq-eq (previous step)

n0 < n, n0 < n + m → copy(ar0, 0, mkarray(n + m), 0, n + m)[n0] = copy(ar1, 0, mkarray(n + m), 0, n + m)[n0] ⊦ ar0[n0] = ar1[n0]

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
copy(ar0, 0, mkarray(n + m), 0, n + m)[n0] = copy(ar1, 0, mkarray(n + m), 0, n + m)[n0], n0 < n + m, n0 < n ⊦ ar0[n0] = ar1[n0]

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ ¬ m + n < m; (s)%fle-01: ⊦ m ≤ n ∧ n < n0 → m < n0; (forward) from specification nat% ⊦ m < n ↔ ¬ n ≤ m; (ss)