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Proof step 12 from proof still-in-rem (previous step)

a ≠ b ∨ count(b, bag0) = 0 ⊦ count(a, bag0) - 0 = 0, a ∈ bag0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 13:
a ≠ b ∨ count(b, bag0) = 0 ⊦ count(a, bag0) = 0, a ∈ bag0

Rule argument

Additional information

Used simplifier rules: ⊦ m - 0 = m; (s)