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Proof step 13 from proof still-in-rem (
previous step
)
a ≠ b ∨ count(b, bag0) = 0 ⊦ count(a, bag0) = 0, a ∈ bag0
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 14
:
⊦ a ∈ bag ↔ count(a, bag) ≠ 0
Rule argument
spec: <toplevel> name: in seq: ⊦ a ∈ bag ↔ count(a, bag) ≠ 0 subst: [bag, a] → [bag0, a] flags: <all paths>
Additional information
Used terms: bag0, a