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Proof step 19 from proof del-two (previous step)

a4 ∈ s, a ∈ s, a2 ∈ s, ∀ a1. a1 = a ∨ ¬ a1 ∈ s ⊦ a0 ∈ s ↔ a0 ∈ ∅ ++ a ++ b, a2 = a, b ∈ s

Heuristic cut applied rule cut formula

And obtained the following new goals

Proof step 20:
a ∈ s, a4 ∈ s, a2 ∈ s, ∀ a1. a1 = a ∨ ¬ a1 ∈ s ⊦ a0 ∈ s ↔ a0 ∈ ∅ ++ a ++ b, a2 = a, b ∈ s

Rule argument

fma: a2 ∈ s

Additional information

Used formulas: a2 ∈ s