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Proof step 20 from proof del-two (
previous step
)
a ∈ s, a4 ∈ s, a2 ∈ s, ∀ a1. a1 = a ∨ ¬ a1 ∈ s ⊦ a0 ∈ s ↔ a0 ∈ ∅ ++ a ++ b, a2 = a, b ∈ s
Heuristic simplifier applied rule simplifier
And obtained the following new goals
Proof step 21
:
a2 ∈ s, a4 ∈ s, a ∈ s, ∀ a1. a1 = a ∨ ¬ a1 ∈ s ⊦ a0 ∈ s ↔ a0 ∈ ∅ ++ a ++ b, a2 = a, b ∈ s
Rule argument
Additional information