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Proof step 2 from proof discard-add2-lels-left (previous step)

0 < j, i + j ≤ j0 ⊦ i < j0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
0 < j ⊦ i < j0, j0 < i + j

Rule argument

Additional information

Used simplifier rules: le-def: ⊦ i ≤ j ↔ ¬ j < i;%forward-le-05: ⊦ i < j ∧ 0 ≤ i → 0 < j;